Full explanation
To solve this problem, we need to understand the relationship between the radii of tangent circles and the triangle formed by their centers.
When two circles with radii r1 and r2 are tangent to each other externally, the distance between their centers is exactly r1+r2.
If we have three circles with radii a, b, and c, the lengths of the sides of the triangle formed by their centers will be: Side 1 = a + b, Side 2 = b + c, Side 3 = a + c.
The problem states that these three sides must form a right triangle.
According to the Pythagorean theorem (A2+B2=C2), the sum of the squares of the two shorter sides must be equal to the square of the longest side (the hypotenuse).
Assuming c is the largest radius, the longest side will be b+c.
Let's assume c>b>a, so the two shorter sides are (a+b) and (a+c), and the equation to check becomes: (a+b)2+(a+c)2=(b+c)2.
Now check each option by computing the triangle's three sides from its radii, then testing whether the two shorter sides squared and summed equal the longest side squared:
A) 2,3,10 -> sides = 5, 12, 13.
Check: 52+122=25+144=169, and 132=169.
They match -- this forms a right triangle.
B) 3,4,5 -> sides = 7, 8, 9.
Check: 72+82=49+64=113, but 92=81. 113≠81 -- not a right triangle.
C) 5,12,13 -> sides = 17, 18, 25.
Check: 172+182=289+324=613, but 252=625. 613≠625 -- not a right triangle.
D) 7,24,25 -> sides = 31, 32, 49.
Check: 312+322=961+1024=1985, but 492=2401. 1985≠2401 -- not a right triangle.
E) 8,15,17 -> sides = 23, 25, 32.
Check: 232+252=529+625=1154, but 322=1024. 1154≠1024 -- not a right triangle.
A common trap in this question is to see triples like (3, 4, 5) or (5, 12, 13) and assume they are the answer because they are famous Pythagorean triples.
However, those are the radii, not the sides of the triangle.
When the radii are 2, 3, and 10, the sides of the triangle become 5, 12, and 13, which do form a perfect right triangle.
Therefore, the correct answer is
A) 2,3,10.